0=-7x^2-2x+5

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Solution for 0=-7x^2-2x+5 equation:



0=-7x^2-2x+5
We move all terms to the left:
0-(-7x^2-2x+5)=0
We add all the numbers together, and all the variables
-(-7x^2-2x+5)=0
We get rid of parentheses
7x^2+2x-5=0
a = 7; b = 2; c = -5;
Δ = b2-4ac
Δ = 22-4·7·(-5)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-12}{2*7}=\frac{-14}{14} =-1 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+12}{2*7}=\frac{10}{14} =5/7 $

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